javascript - How to Move Element With Script Element Without Re-Executing Script with jQuery? -

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मेरे पास यह कोड स्निपेट है: 

  & lt; div id = "div1" & gt; & Lt; / div & gt; & Lt; div id = "div2" & gt; & Lt; h3 & gt; यह सामग्री है & lt; / h3 & gt; & Lt; स्क्रिप्ट प्रकार = "टेक्स्ट / जावास्क्रिप्ट" & gt; चेतावनी ('यह सामग्री है'); & Lt; / स्क्रिप्ट & gt; & Lt; / div & gt; & Lt; स्क्रिप्ट प्रकार = "टेक्स्ट / जावास्क्रिप्ट" & gt; jQuery ( 'div # DIV2') appendTo ( 'div # div1')। & Lt; / स्क्रिप्ट & gt;

इस कोड का इस्तेमाल करते हुए, अलर्ट संदेश दो बार दिखाया जाएगा (एक बार जब पृष्ठ लोड हो रहा है, और तब जब jQuery स्क्रिप्ट को फिर से कार्यान्वित करता है जब यह एपेंडटो विधि कार्यान्वित करता है?

JQuery के उपयोग के लिए आसानी से तत्व (जिस पर स्क्रिप्ट टैग है) को फिर से बिना जावास्क्रिप्ट के निष्पादन के लिए स्थानांतरित करने का कोई भी विचार?

धन्यवाद

एक बार जब और <स्क्रिप्ट> gtc: निष्पादित हो गया है, तब आपको इसकी ज़रूरत नहीं है, इसलिए आप इसे # div2 । 

  $ ('# div2 स्क्रिप्ट')। निकालें (); $ ('# div2')। AppendTo ('# div1');

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