double - How do I convert a Python float to a hexadecimal string in python 2.5? Nonworking solution attached -

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What I really need to do is export a floating point number C with no exact loss.

I did this in Python: 

  import math import structure x = math.sqrt (2) print struct.unpack ('ii', struct.pack ('d ', X)) # print (1719614413, 1073127582) and try this in CI:  
  #include  # Include & lt; Stdio.h & gt; Int main (zero) {unsigned long long x [2] = {1719614413, 1073127582}; LX long; Double XF; LX = (X [0] <<32 <32 X [1]; Xf = (double) lx; Printf ("% lf \ n", xf); Return 0; }  
 
 but found in CI: 
 
 7385687666638364672.000000 and not sqrt (2). 
 
 What am I missing? 
 
 Thank you.

Python code appears to be working. The problem is in C code: You have the long filled right , but then you change the integer values ​​directly to the floating point, instead of re-defining the byte < Code> double . If you throw some points or address it, then it works: 

  jkugelman $ cat float.c #include & lt; Stdio.h & gt; Int main (zero) {unsigned long x [2] = {1719614413, 1073127582}; Double D = * (double *) x; Printf ("% f \ n", d); Return 0; } Jkugelman $ gcc -o float float.c jkugelman $ ./float 1.414214

Also note that double (and float ) Is % f , not % lf . % lf is for long double .


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