regex - Shell script to extract certain fields from XML files -

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I'm new to Linux open and I'm not able to understand regex.

Here's my question: I have a directory named / var / visitors and under this directory, I have a , b , c , d . In each of these directories, there is a file named list.xml and here, for example, list.xml to / var / visitors / a : 

  & lt; Key & gt; Name & lt; / Key & gt; & Lt; String & gt; Mr. Jones & lt; / String & gt; & Lt; Key & gt; Id & lt; / Key & gt; & Lt; String & gt; 51 & lt; / String & gt; & Lt; Key & gt; Lane & lt; / Key & gt; & Lt; String & gt; 53151334 & lt; / String & gt;

I have to merge the name field with its corresponding string and merge the id field with its associated string. I do not need any other fields. 

  Name: Mr. Jones ID: 51 --- Name: MS Maggi Id: 502

Here's how far I got:

< Find pre> cd / var / visitor-name "list.xml" | Xerose grapes

Please help.

is not elegant, but it will work:

Name "list.xml" | X-cat | Tr-d "\ n" | Sed's / & lt; \ / String> / \ N / g '| | Sed's / & lt; \ / Key> /: / G '| | Sed's / & lt; [^ & Gt;] * & gt; //g '| | Like "name: | id:" | In fact it does this:
  • Delete all new lines < / Li>
  • Remove all element content (between & lt; and>)
  • Save only names and id fields (drop all other) < Li> Add --- Separator

    Sample output: 

      --- Name: Greg ID: 52 --- Name: Amy ID: 53 - - Name: Mr. Jones ID: 51

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